The perimeter of a rectangle is 78 m the width is 7 m less than the length find the length and the width of the rectangle

Step-by-step explanation:

let the length of the rectangle be x

hence, the width of the rectangle is (x-7)

perimeter of a rectangle=2 (l+w)

78=2 (x+x-7)

78=2 (2x-7)

78=4x-14

4x=78+14

x=92/4

therefore x or length=23 m

hence, width will be (x-7) or (23-7) = 16m

length = 23 m

width = 16 m

Step-by-step explanation:

perimeter of a rectangle = p = 2*L+2*w

p = 78 = 2*L+2*w

w=width

L=length

w = L-7

78 = 2*L+2*w

78 = 2L+2 (L-7)

78 = 2L+2L - 14

78+14 = 4L

4L=92

L=92/4

L = 23 m = length

so we have:

w = L-7

w = 23-7 = 16 m = width