Un proyectil se dispara con una velocidad inicial de 450 pies / seg y con un angulo de elevacion de 30° sobre la horizontal, calcular

a) su posición y velocidad despues de 8s,

b) la altura máxima

A projectile is fired with an initial velocity of 450 ft / sec and with an elevation angle of 30 ° above the horizontal, calculate a) its position and speed after 8s,

The position after 8 seconds will be as follows

horizontal distance:

x=V * t

x=450*8

=3600 ft

b) the maximum height reached will be given by:

H=[v² sin²θ]/2g

Plugging in the values we get:

H=[450²*sin²30] / (2*10)

H=2,531.25 ft