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27 January, 03:28

The sum of the first and third of three consecutive even integers is 132. Find the three even integers

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  1. 27 January, 03:57
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    let's represent even integers as n. so we would do n+2 + n+4 + n+6=132 3n+12=132

    3n=120 n=40. so substitute 40 for n to get the even integers
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