Find the root (s) of f (x) = (x + 5) 3 (x - 9) 2 (x + 1). - 5 with multiplicity 3 5 with multiplicity 3 - 9

-5, multiplicity 3; + 9, multiplicity 2; - 1

Step-by-step explanation:

The roots of f (x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f (x) = (x+5) ^3 (x-9) ^2 (x+1) has roots ...

-5 with multiplicity 3 + 9 with multiplicity 2 - 1