A person has 22 coins, all nickels and dimes, worth one dollar and 40 cents. If n is the number of nickels and d is the number of dimes, which system of equations could represent this problem?

n+d=1.40

0.05n+0.1d=22

n+d=22

n+d=1.40

n+d=22

0.05n+0.10d=1.40

Question

Damian Bauer

Mathematics

20 July, 20:28

A person has 22 coins, all nickels and dimes, worth one dollar and 40 cents. If n is the number of nickels and d is the number of dimes, which system of equations could represent this problem?

n+d=1.40

0.05n+0.1d=22

n+d=22

n+d=1.40

n+d=22

0.05n+0.10d=1.40

+2

Answers (1)

Know the Answer?

Maeve Mason · Answer 1

The third system, because your total amount of coins (n+d) is 22 coins. Since a nickel is worth $0.05, and a dime is worth $0.10, you multiply n by 0.05, and multiply d by 0.10 to get the financial value of the coins in dollars.

A person has 22 coins, all nickels and dimes, worth one dollar and 40 cents. If n is the number of nickels and d is the number of dimes, which system of equations could represent this problem?n+d=1.400.05n+0.1d=22n+d=22n+d=1.40n+d=220.05n+0.10d=1.40

A person has 22 coins, all nickels and dimes, worth one dollar and 40 cents. If n is the number of nickels and d is the number of dimes, which system of equations could represent this problem?

n+d=1.40

0.05n+0.1d=22

n+d=22

n+d=1.40

n+d=22

0.05n+0.10d=1.40