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26 July, 04:35

Determine values of c and d for √which the equation √ (3x-1) - √ (cx + d) = 0 has no solution.

I added √ (cx + d) to both sides and squared them ... 3x-1 = cx + d

rearranged to get 3x - cx = d + 1; then factored out x to get x (3 - c) = d + 1

then divided x = (d + 1) / (3 - c) therefore c ≠ 3 what about d?

I'm not sure what question is asking when looking for c and d

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  1. 26 July, 04:57
    0
    So there is no solution when it is false so your reasoning is correct, it divides by zero making it false so c must be 3 and d can be any number. not completely sure
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