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10 June, 15:29

A tumor is injected with 0.1 grams of lodine-125, which has a decay rate of 1.15% per day. To the nearest day, how long will it take for half of the lodine-125 to decay?

days

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  1. 10 June, 15:51
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    hi,

    1 - 0.015 = 0.985

    so we have : 0.1 * 0.985 ^n = 0.05

    0.985^n = 0.05 / 0.1

    0.985^n = 0.5

    n = ln (0.5) / ln (0.985)

    n ≈ 46

    Let's check : 0.1*0.985^46 ≈0.0498
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