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23 October, 02:50

The sum of two numbers is 32. the sum of 3 times the larger and 7 times the smaller is 128

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  1. 23 October, 02:55
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    Smaller number = 8 (x)

    Larger number = 24 (y)

    Step-by-step explanation:

    x+y=32

    7x+3y=128

    Solving by Elimination

    -3x-3y = - 96

    7x+3y=128

    4x=32

    4x/4=32/4

    x=8

    -7x-7y = - 224

    7x+3y=128

    -4y = - 96

    -4y/-4 = - 96/-4

    y=24

    Check answer

    x+y=32

    8+24=32

    7x+3y=128

    7 (8) = 3 (24) = 138

    56+72=128

    128=128
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