The population in a particular country is growing at the rate of 1.9% per year. If

5,092,000 people lived there in 1999, how many will there be in the year 2006? Round to

the nearest ten-thousand.

Question

Yesenia Wallace

Mathematics

28 December, 17:55

The population in a particular country is growing at the rate of 1.9% per year. If

5,092,000 people lived there in 1999, how many will there be in the year 2006? Round to

the nearest ten-thousand.

+2

Answers (1)

Know the Answer?

Edwin Dorsey · Answer 1

6,770,000

Step-by-step explanation:

first you find out how many years apart it is. which is 7. Then you multiply that by 1.9 which equals 13.3. than You multiply 5,092,000 by 13.3 to get 6,700,000.

The population in a particular country is growing at the rate of 1.9% per year. If5,092,000 people lived there in 1999, how many will there be in the year 2006? Round tothe nearest ten-thousand.

The population in a particular country is growing at the rate of 1.9% per year. If

5,092,000 people lived there in 1999, how many will there be in the year 2006? Round to

the nearest ten-thousand.