Find the length and width of a rectangle whose perimeter is 26 feet and whose area is 42 square feet

Answer: length = 7 feet's

Width = 6 feets

Step-by-step explanation:

Perimeter of a rectangle is the distance round the rectangle.

Perimeter of rectangle is expressed as

2 (length + width)

The perimeter of the given rectangle is 26 feet. Therefore

2 (L + W) = 26

Dividing by 2,

L+W = 13

The area of a rectangle is expressed as length * width

The given area is 42 square feet. Therefore,

L*W = 42

Substituting L = 13 - W into LW = 42, it becomes

W (13-W) = 42

13W - W^2 = 42

W^2 - 13W + 42 = 0

W^2 - 7W - 6W + 42 = 0

W (W - 7) - 6 (W - 7) = 0

(W-6) (w-7) = 0

W-6 = 0 or W-7=0

W=6 or W = 7

L = 13-6 or L = 13-7

L = 7 or L = 6