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6 May, 13:48

Find the length and width of a rectangle whose perimeter is 26 feet and whose area is 42 square feet

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  1. 6 May, 14:01
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    Answer: length = 7 feet's

    Width = 6 feets

    Step-by-step explanation:

    Perimeter of a rectangle is the distance round the rectangle.

    Perimeter of rectangle is expressed as

    2 (length + width)

    The perimeter of the given rectangle is 26 feet. Therefore

    2 (L + W) = 26

    Dividing by 2,

    L+W = 13

    The area of a rectangle is expressed as length * width

    The given area is 42 square feet. Therefore,

    L*W = 42

    Substituting L = 13 - W into LW = 42, it becomes

    W (13-W) = 42

    13W - W^2 = 42

    W^2 - 13W + 42 = 0

    W^2 - 7W - 6W + 42 = 0

    W (W - 7) - 6 (W - 7) = 0

    (W-6) (w-7) = 0

    W-6 = 0 or W-7=0

    W=6 or W = 7

    L = 13-6 or L = 13-7

    L = 7 or L = 6
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