What is the domain of the functionf (x) = sqrt 9x? all real numbers all real numbers greater than but not equal to 0 all real number less than or equal to 0 all real numbers greater than or equal to 0

The domain is all real numbers greater than or equal to zero

Step-by-step explanation:

∵ f (x) = √9x

∴ The domain is all values of x ≥ 0

because if x = number less than zero it will be negative

There is no value in the real number for √-ve values

∴ The domain is all real numbers ≥ 0

Domain : [0, ∞) x (equal to 0 all real numbers greater than or equal to 0).

Step-by-step explanation:

The given function is f (x) = √9x = 3√x

For this function f (x) is defined only if x ≥ 0 because for x < 0 the function is not defined.

f (-x) = 3√ (-x) which is not defined.

Therefore domain of this function is domain: [0, ∞) x