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24 July, 09:05

What is the focus of the parabola?

y=-14x2-2x-2

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  1. 24 July, 09:35
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    First, we need to transform the equation into its standard form (x - h) ²=4p (y - k).

    Using completing the square method:

    y = - 14x² - 2x - 2

    y = - 14 (x² + 2x/14) - 2

    y = - 14 (x² + 2x/14 + (2/28) ²) - 2 + (2/28) ²

    y = - 14 (x + 1/14) ² - 391/196

    -1/14 (y + 391/196) = (x + 1/14) ²

    This is a vertical parabola and its focus (h, k + p) is (-1/14, - 391/196 + 1/56) = (-1/14, - 775/392).

    Or (-0.071,-1.977).
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