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Esmeralda
Mathematics
24 July, 09:05
What is the focus of the parabola?
y=-14x2-2x-2
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Jaylene Christensen
24 July, 09:35
0
First, we need to transform the equation into its standard form (x - h) ²=4p (y - k).
Using completing the square method:
y = - 14x² - 2x - 2
y = - 14 (x² + 2x/14) - 2
y = - 14 (x² + 2x/14 + (2/28) ²) - 2 + (2/28) ²
y = - 14 (x + 1/14) ² - 391/196
-1/14 (y + 391/196) = (x + 1/14) ²
This is a vertical parabola and its focus (h, k + p) is (-1/14, - 391/196 + 1/56) = (-1/14, - 775/392).
Or (-0.071,-1.977).
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