Find all unique zeros of the function fix) 8x - 64x + 160x - 128-

Answer: Lets divide by 8. My god, those coefficients are large.

x^3 - 8x^2 + 20x - 16 = 0

Possible integral roots are: + 1, - 1, + 2, - 2, + 4, - 4, + 8, - 8

If x = 2, f (x) = 8 - 32 + 40 - 16 = 0

Hence, x-2 is a factor.

Use synthetic division to get: x^2 - 6x + 8 = (x-4) (x-2).

Therefore, there are two integral roots: + 2 and + 4.