If the vertices of triangle bcd are B (-3,3) and c (3,5) and d (-1,0). what is the perimeter?

A) 10.98

B) 11.41

C) 16.33

D) 17.00

D (BD) = √ (2² + 3²) = √ (4+9) = √13 ≈ 3.61

d (DC) = √ (4² + 5²) = √ (16+25) = √41 ≈6.40

d (CB) = √ (6² + 2²) = √ (36+4) = √40 ≈ 6.32

The perimeter: 3.61 + 6.40 + 6.32 = 16.33

Answer:

C) 16.33