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27 September, 05:17

The ages of three siblings total 32 years. The middle child is 4 years older than the youngest, and the eldest is twice as old as the youngest. How old is each child?

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  1. 27 September, 05:19
    0
    Oldest=14

    Middle=11

    Youngest=7

    Step-by-step explanation:

    Oldest is 2x youngest (7*2=14)

    one you figure out the youngest (7) then * 2 to get eldest (14)

    32-7=25

    25-14=11<--age of middle child that is 4 years older than youngest (7+4=11)
  2. 27 September, 05:36
    0
    x = 7

    y = 11

    z = 14

    Step-by-step explanation:

    x + y + z = 32

    Let's say the youngest is x, middle is y and oldest is z.

    y = x+4 (age of the youngest + 4)

    z = 2x (twice as old)

    We can replace y and z in the main equation above with these values that contain x.

    x + (x + 4) + 2x = 32

    4x = 28, divide both sides by 4

    x = 7

    y = x + 4 = 7 + 4 = 11

    z = 2x = 2*7 = 14

    And to check: 7 + 11 + 14 = 32
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