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19 July, 00:03

It has an amplitude of 3 and a period of 4pi/5 Find the equation of this wave as a sine function.

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  1. 19 July, 00:05
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    y = 3 sin 2.5 x

    Step-by-step explanation:

    Given that a sine function has an amplitude of 3 and a period of 4pi/5

    There is no phase shift or vertical shift. Hence y would be y only and x is x only.

    Consider original sine function y = sinx

    This has period 2pi and amplitude = 1

    Since new amplitude is 3, we must have coefficient of sinx as 3

    i. e. y = 3 sinx makes the amplitude 3.

    To change period from 2pi to 4pi/5, we change the coefficient of x from 1 to

    5/2

    i. e. y = 3 sin 2.5 x is the equation of this function.
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