If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1. Determine the original fraction. Which of the following equations represents "If the numerator of a fraction is increased by 3, the fraction becomes 3/4"?

Let n = numerator

d = denominator

n+3/d = 3/4

n / (d-7) = 1

Which of the following equations represents "If the numerator of a fraction is increased by 3, the fraction becomes 3/4"?

The equation is (n+3) / d = 3/4

For this case, the original fraction is:

x / y

Where,

x = numerator

y = denominator:

If the numerator of a fraction is increased by 3, the fraction becomes 3/4:

(x + 3) / y = 3/4

If the denominator is decreased by 7, the fraction becomes 1:

x / (y-7) = 1

Solving the system of equations we have:

x = 9

y = 16

The original fraction is:

9/16

Answer:

the original fraction is:

9/16

"If the numerator of a fraction is increased by 3, the fraction becomes 3/4" is:

(x + 3) / y = 3/4