Square root of 12 is between 3& 4, 4& 5 5& 6 6& 7

Ok easy way is let's say we want to ifnd if the square root of a nubmer x is between the numbers 3 and 4 what we would do is 3^2=9 4^2=16 and if x is between 9 and 16, then the square root of x is between 3 and 4 so 12 3^2=9 4^2=16 12 is between 9 and 16 therefor squaer root of 12 is between 3&4

First divide everthing

12^3=4

12^4=3

12^4=3

12^5=2.4

12^6=2

12^7=1 5/7

answer=3&4