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12 June, 13:01

A diver is on the 10m platform, preparing to perform a dive. the diver's height above the water, in metres, at time t can be modelled using the equation : h (t) = - 4.9 (t) ^2 + 2t + 10 ... Estimate the rate at which the diver's height above the water is changing as the diver enters the water. be sure to include at least 3 intervals from booth sides in your table. I think its instantaneous rate of change ...

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  1. 12 June, 13:17
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    We are given with 2 which means the initial velocity is 2 m/s and the height is 10 m initially. we are given the expression h (t) = - 4.9 (t) ^2 + 2t + 10. we can also use 2ay = Vf2 - Vo2

    for three intervals:

    2*9.8*7 = Vf2 - 10^2; Vf is 15.40 m/s

    2*9.8*8 = Vf2 - 10^2; Vf is 16.02 m/s

    2*9.8*9 = Vf2 - 10^2; Vf is 16.63 m/s
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