Peyton and her children went into a restaurant and where they sell drinks for $3 each

and tacos for $4 each. Peyton has $40 to spend and must buy at least 10 drinks and

tacos altogether. If Peyton decided to buy 4 drinks, determine all possible values for

the number of tacos that she could buy. Your answer should be a comma separated

list of values. If there are no possible solutions, submit an empty answer.

Answer: 6 ≤ x ≤ 7

Step-by-step explanation:

Let x represent the number of tacos that she could buy.

If Peyton decided to buy 4 drinks and he must buy at least 10 drinks and tacos altogether, it means that

x + 4 ≥ 10

x ≥ 10 - 4

x ≥ 6

The restaurant sells drinks for $3 each and tacos for $4 each. If Peyton has $40 to spend, it means that

3 * 4 + 4x ≤ 40

12 + 4x ≤ 40

4x ≤ 40 - 12

4x ≤ 28

x ≤ 28/4

x ≤ 7

Therefore, the possible values for

the number of tacos that she could buy is

6 ≤ x ≤ 7

6, 7

Step-by-step explanation:

Drinks cost = $3*4=$12

Remaining amount=$28

Maximum number of tacos that can be bought=$28:4=7

Min number of Tacos=10-4=6

Possible values are between 6 and 7. Hence 6, 7.