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24 September, 00:44

Peyton and her children went into a restaurant and where they sell drinks for $3 each

and tacos for $4 each. Peyton has $40 to spend and must buy at least 10 drinks and

tacos altogether. If Peyton decided to buy 4 drinks, determine all possible values for

the number of tacos that she could buy. Your answer should be a comma separated

list of values. If there are no possible solutions, submit an empty answer.

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Answers (2)
  1. 24 September, 01:03
    0
    Answer: 6 ≤ x ≤ 7

    Step-by-step explanation:

    Let x represent the number of tacos that she could buy.

    If Peyton decided to buy 4 drinks and he must buy at least 10 drinks and tacos altogether, it means that

    x + 4 ≥ 10

    x ≥ 10 - 4

    x ≥ 6

    The restaurant sells drinks for $3 each and tacos for $4 each. If Peyton has $40 to spend, it means that

    3 * 4 + 4x ≤ 40

    12 + 4x ≤ 40

    4x ≤ 40 - 12

    4x ≤ 28

    x ≤ 28/4

    x ≤ 7

    Therefore, the possible values for

    the number of tacos that she could buy is

    6 ≤ x ≤ 7
  2. 24 September, 01:07
    0
    6, 7

    Step-by-step explanation:

    Drinks cost = $3*4=$12

    Remaining amount=$28

    Maximum number of tacos that can be bought=$28:4=7

    Min number of Tacos=10-4=6

    Possible values are between 6 and 7. Hence 6, 7.
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