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Armani Osborn
Mathematics
24 June, 15:15
Given f (x) = x^2-x; find f (-5)
+5
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Marcel Yang
24 June, 15:31
0
Plug in - 5 where X is.
f ( - 5) = ( - 5) ^2 - ( - 5).
( - 5) ( - 5) = 25 so now we have 25 - ( - 5). Because there are two negatives back to back, the number becomes a positive so the equation becomes 25 + 5 = 30.
f ( - 5) = 30.
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