Ask Question
24 October, 23:18

The yard behind the Cindy's house is rectangular in shape and has a perimeter of 72 feet. If the length l of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet?

+4
Answers (1)
  1. 24 October, 23:40
    0
    Let the width of the yard be w.

    Since the length is 18feet longer, l = w + 18

    Perimeter for rectangle = 2 (l + w)

    2 (l + w) = 72

    2 (w+18 + w) = 72 Divide 2 on both sides

    (w + 18 + w) = 36

    2w + 18 = 36

    2w = 36 - 18

    2w = 18 Divide 2 on both sides

    w = 18/2

    w = 9

    Recall, length l = w + 18, l = 9 + 18 = 27

    Hence width, w = 9, length, l = 27

    Area of rectangle = l * w = 27 * 9 = 243

    Area of rectangular yard = 243 square feet.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The yard behind the Cindy's house is rectangular in shape and has a perimeter of 72 feet. If the length l of the yard is 18 feet longer ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers