To solve this system of equations by elimination, what operation could be used to eliminate the y-variable and find the value of x? 2x - 4y = 6 - 3x + 3y = 12

2x - 4y = 6

-3x + 3y = 12

In order to find x (first) you need to eliminate y

3 (2x - 4y = 6)

4 (-3x + 3y = 12)

6x - 12y = 18

-12x + 12y = 48

y cancels out and you should now have

6x - 12x = 18 + 48

Simplify the equation;

-6x = 66

Divide both sides by - 6 to get x by itself,

x = 11