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26 March, 07:00

Find the range for the function k (n) = 2n2 when D = {-2, 1, 3}. R = {2, 8, 18} R = {2, 18, 36} R = {4, 12, 27} R = {4, 12, 16}

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  1. 26 March, 07:19
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    K (n) = 2n^2 ... where domain (n) = - 2

    k (-2) = 2 (-2^2) = 2 (4) = 8

    k (n) = 2n^2 ... where n = 1

    k (1) = 2 (1^2) = 2 (1) = 2

    k (n) = 2n^2 ... where n = 3

    k (3) = 2 (3^2) = 2 (9) = 18

    so ur range k (n) = { 2,8,18}
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