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24 June, 05:30

Simutaneous equation by substitution:y+2x=0,4x+y=3 ... solve for x and y

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  1. 24 June, 05:32
    0
    1y + 2x = 0 ⇒ - 2x - 1y = 0

    4x + 1y = 3 ⇒ 4x + 1y = 3

    2x = 3

    2 2

    x = 1.5

    4 (1.5) + y = 3

    6 + y = 3

    - 6 - 6

    y = - 3

    (x, y) = (1.5, - 3)
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