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13 February, 14:33

Which pair of complex numbers has a real-number product? A) (1 + 3i) (6i) B) (1 + 3i) (2 - 3i) C) (1 + 3i) (1 - 3i) D) (1 + 3i) (3i)

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  1. 13 February, 14:47
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    The answer to the question above is letter "C. (1 + 3i) x (1 - 3i) ". Evidently, the second factor is the conjugate of the first which will lead to the difference of two squares, 1 - (3i) ². This will simplify into 1 - (-9) or 10.
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