How much horsepower would a Challenger SRT® Hellcat Redeye Widebody need to tow the SS Delphine up the industry standard: Davis Dam Grade Climb?

Pro Tips:

Davis Dam assumed grade = 7% Air density is sea level conditions (.002377 slugs/f^t3) w (weight) of the SS Delphine + trailer + Redeye = 3,922,000 + 150,000 + 4451 Lbs Crr = coefficient of rolling resistance =.015 Assume Combined CDA is 1555 ft^2 SAE J2807 (Davis Dam Grande Climb) - min speed is 40mpg (59 ft/s) F (drag) = 1/2p x V^2 x C (d) A F (rolling resistance) = W x cos x Crr F (weight) = W x sin F (sum) = F (drag) + F (rr) + F (weight) P = F (sum) XV convert to horsepower = P (1hp/550ft lbf/sec)

37769 hp

Step-by-step explanation:

from the pro tips given w (weight of the SS Delphine + trailer + Redeye) = 3922000 + 150000 + 4451 Lbs Crr = 4076451 ibf

coefficient of rolling resistance = 0.015

Combined CDA = 1555 ft ^2

to get Ф = tan ⁻¹ (0.07) = 4.0041 degrees

To get F (w) you will multiply it with sin Ф

= F (w) = 4076451 ibf * sin (4.0041) = 284655.02 Ibf

to calculate F (rr) you will multiply it with cos Ф

F (rr) = 4076451 ibf * 0.015 * cos (4.0041) = 60997.50 ibf

the total sum of F (force) will be

F (rr) + F (w)

= 60997.50 + 284655.02 = 352085.82 Ibf

therefore P (power) will be

p = 352085.82 ibf * 59 ft/s = 20773063.27 ft*ibf/s

to calculate how much horsepower the challenger will need to tow the SS Delphine will be calculated as below

HP = (20773063.27 ft*ibf/s) * (1 hp / 550 ft*ibf/s) = 37769.21 = 37769 hp

Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.