Marty has 210 coins and 48 of them are quarters. One-third of the remaining coins are dimes. How many dimes does Marty have? How do you solve it? I did 210 - 48 = 162 and 162 x 1/3, 0.3.
A. 162
B. 108
C. 54
D. 22
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Home » Mathematics » Marty has 210 coins and 48 of them are quarters. One-third of the remaining coins are dimes. How many dimes does Marty have? How do you solve it? I did 210 - 48 = 162 and 162 x 1/3, 0.3. A. 162 B. 108 C. 54 D. 22