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Finnegan Bryan
Mathematics
30 July, 12:25
What is the factored form of 9X^2+12X+4
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Kian Gates
30 July, 12:28
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This is of the form ax^2+bx+c. To factor a quadratic like this you want to find two values, j and k, that satisfy two conditions.
jk=ac and j+k=b ... in this case:
jk=ac=36 and j+k=b=12, so j and k must be 6 and 6
Now you replace bx with jx and kx in the original equation which gives you:
9x^2+6x+6x+4 now factor the first and second pair of terms ...
3x (3x+2) + 2 (3x+2) which is equal to:
(3x+2) (3x+2) which is just:
(3x+2) ^2
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Dylan Zhang
30 July, 12:52
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(3X+2) ^2 or (3X+2) x (3X+2)
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