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13 September, 17:04

X^2 - 4x - 12 = 0 Factor and solve

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  1. 13 September, 17:32
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    Ax^2+bx+c=0

    find what 2 numbers multiply to get c and add to get b

    x^2-4x-12

    b=-4

    c=-12

    x times y=-12

    x+y=-4

    factor - 12

    -1, 12

    -2,6

    -3,4

    add

    -1+12=11

    -2+6=4

    -3+4=1

    the one that works is - 2 and 6 because they can be reversed to make - 6 and 2 which multiploy to get - 12 and add to get - 4 so

    split it up into

    x^2-4x-12 = (x-6) (x+2) = 0

    set each to zero

    x-6=0

    add 6

    x=6

    x+2=0

    subtract 2

    x=-2

    x=6 or - 2
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