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Mathematics
13 September, 17:04
X^2 - 4x - 12 = 0 Factor and solve
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Victoria Carey
13 September, 17:32
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Ax^2+bx+c=0
find what 2 numbers multiply to get c and add to get b
x^2-4x-12
b=-4
c=-12
x times y=-12
x+y=-4
factor - 12
-1, 12
-2,6
-3,4
add
-1+12=11
-2+6=4
-3+4=1
the one that works is - 2 and 6 because they can be reversed to make - 6 and 2 which multiploy to get - 12 and add to get - 4 so
split it up into
x^2-4x-12 = (x-6) (x+2) = 0
set each to zero
x-6=0
add 6
x=6
x+2=0
subtract 2
x=-2
x=6 or - 2
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