Solve for x. - ax 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a

Question

Brice Atkinson

Mathematics

28 July, 22:27

Solve for x. - ax 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a

+5

Answers (1)

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Braylen Thornton · Answer 1

-ax + 3b > 5

Subtract 3b: - ax > 5 - 3b

Diuvide by - a, which implies to change the sign > to <:

x < [5 - 3b] / (-a) or x < [3b - 5]/a ... both are equivalent

That is second option.