Ask Question
22 April, 09:25

When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth?

0
Answers (1)
  1. 22 April, 10:59
    0
    The original number was 36.7.

    Step-by-step explanation:

    Multipliers:

    The multiplier for a increase of a% is 1 + a/100.

    The multiplier for a decrease of b% is 1 - b/100.

    In this question:

    The original value is x.

    Increased by 28%, so we have that 1 + (28/100) = 1.28x. Equals 47. We have to find x.

    1.28x = 47

    x = 47/1.28

    x = 36.7

    The original number was 36.7.
Know the Answer?