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13 January, 12:16

What is the distance between (3, 7 and (15, 16)

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  1. 13 January, 12:36
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    D = √ ((x2 - x1) ^2 + (y2 - y1) ^2)

    D = √ ((15-3) ^2 + (16 - 7) ^2)

    D = √ (12^2 + 9^2)

    D = √ (144 + 81)

    D = √225

    D = 15
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