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9 August, 18:27

Suppose we have an unfair 6-sided die. the die has been altered sothat the number 5 is twice as likely to appear as any of the other five outcomes. what are the probabilities of each possible outcome

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  1. 9 August, 18:31
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    The probability of getting "5" = 2/7

    The probability of getting "1" = 1/7

    The probability of getting "2" = 1/7

    The probability of getting "3" = 1/7

    The probability of getting "4" = 1/7

    The probability of getting "6" = 1/7
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