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17 February, 14:49

A person wishes to mix coffee worth $9 per lb with coffee worth $3 per lb to get 150 lb of a mixture worth $5 per lb. How many pounds of the $9 and the $3 coffees will be needed

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  1. 17 February, 15:11
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    50 lb of $9 coffee and 100 lb of $3 coffee

    Step-by-step explanation:

    Let x = the pounds of $9 coffee. Then

    150 - x = the pounds of $3 coffee.

    We can calculate the value of the coffee in each mixture.

    x lb * $9/lb + (150 - x) lb * $3/lb = 150 lb * $5/lb

    9x + 3 (150 - x) = 750

    Distribute the 3 9x + 450 - 3x = 750

    Combine like terms 450 + 6x = 750

    Subtract 450 from each side 6x = 300

    Divide each side by 6 x = 50 lb of $9 coffee

    150 - x = 100 lb of $3 coffee

    The person must mix 50 lb of $9/lb coffee with 100 lb of $3/lb coffee to get 150 lb of $5/lb coffee.

    Check:

    50 * 9 + 100 * 3 = 750

    450 + 300 = 750

    750 = 750
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