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27 September, 17:04

How to solve 7 (4*1/2) + 3 (5*1/3) + 2 (-3*1/2

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  1. 27 September, 17:08
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    Multiple: 4 * 1 / 2 = 4 · 1 = 4 / 2 = 2 · 2

    1 · 2 1 · 2 = 2

    Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD (4, 2) = 2

    Multiple: 7 * 2 = 14

    Multiple: 5 * 1 / 3 = 5 · 1

    1 · 3 = 5 / 3

    Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD (5, 3) = 1

    Multiple: 3 * 5 / 3 = 3 · 5

    1 · 3 = 15 / 3 = 5 · 3

    1 · 3 = 5

    Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD (15, 3) = 3

    Add: 14 + 5 = 19

    Multiple: - 3 * 1 / 2 = - 3 · 1

    1 · 2 = - 3 / 2 = - 1.5 · 2

    1 · 2

    Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD (-3, 2) = 2

    Multiple: 1/2 * (-3 / 2) = 2 · (-3)

    1 · 2 = - 6 / 2 = - 3 · 2

    1 · 2 = - 3

    Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD (-6, 2) = 2

    Add: 19 + (-3) = 16

    7 (4*1/2) + 3 (5*1/3) + 2 (-3*1/2) = 16 / 1 = 16
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