Mr. lee had a bag of red beans and a bag of black beans. 20% of the total number of beans were black, and there were 180 ounces more red beans than black beans. he transferred some red beans to the bag containing black beans, so that, the bag now contained 30% of the total number of beans. How many ounces of beans were there in the bag of mixed beans

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19 May, 22:39

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Jorge · Answer 1

R = b+180

b =.2 (r+b)

so,

b = 60

r = 240

Total beans = 300 oz

After the transfer, 30% = 90 oz