I have a triangular garden such that the largest side is 6 ft less than twice the smallest and medium side is 5 ft larger than the smallest side. If the total perimeter of the garden is 47 ft, what are the lengths of the three sides

Question

Cierra

Mathematics

8 June, 03:22

I have a triangular garden such that the largest side is 6 ft less than twice the smallest and medium side is 5 ft larger than the smallest side. If the total perimeter of the garden is 47 ft, what are the lengths of the three sides

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Anastasia Horton · Answer 1

Given:

Triangular garden

smallest side: x

medium side: x + 5ft

largest side: 2x - 6ft

Perimeter: 47 ft.

Perimeter = smallest side + medium side + largest side

47 ft = x + x + 5ft + 2x - 6ft

47 ft - 5ft + 6ft = 4x

48ft = 4x

48ft / 4 = 4x / 4

12 ft = x

smallest side: x = 12 feet

medium side: x + 5ft = 12ft + 5ft = 17 ft

largest side: 2x - 6ft = 2 (12ft) - 6ft = 24ft - 6ft = 18ft

Perimeter: smallest + medium + largest

47ft = 12ft + 17ft + 18ft

47ft = 47ft