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25 January, 07:37

an airplane climbs at a rate of 66.8 feet per minute. It descends at twice the rate that it climbs. Assuming it descends at a constant rate, how many feet will the aitplane descend in 30 minutes.

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  1. 25 January, 07:49
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    The distance formula is distance (d) = rate (r) x time (t). In this problem we are trying to find the distance and we are given the rate which in this case is 66.8 feet per minute * 2 and the time is 30 minutes. We can substitute this into our equation we get:

    D = 133.6 x 30. When we multiply this out we get D = 4008 ft.
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