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5 January, 12:22

Graph

A third degree polynomial with 2 zeros

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Answers (1)
  1. 5 January, 12:31
    0
    For a third degree polynomial, we need 3 linear factors.

    Since

    5

    and

    2

    i

    are roots (zeros), we know that

    x

    -

    5

    and

    x

    -

    2

    i

    are factors.

    If we want a polynomial with real coeficients, then the complex conjugate of

    2

    i

    (which is

    -

    2

    i

    ) must also be a root and

    x

    +

    2

    i

    must be a factor.

    One polynomial with real coefficients that meets the requirements is

    (

    x

    -

    5

    )

    (

    x

    -

    2

    i

    )

    (

    x

    +

    2

    i

    )

    =

    (

    x

    -

    5

    )

    (

    x

    2

    +

    4

    )

    =

    x

    3

    -

    5

    x

    2

    +

    4

    x

    -

    20

    Any constant multiple of this also meets the requirements.

    For example

    7

    (

    x

    3

    -

    5

    x

    2

    +

    4

    x

    -

    20

    )

    =

    7

    x

    3

    -

    35

    x

    2

    +

    28

    x

    -

    140
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