Ask Question
17 February, 04:16

Order the steps to solve the equation log3 (x + 2) = log3 (2x2 - 1) from 1 to 6. 0 = (2x - 3) (x + 1)

0 = 2x2 - x - 3

Potential solutions are - 1 and 3

2

.

2x - 3 = 0 or x + 1 = 0

x + 2 = 2x2 - 1

3log3 (x + 2) = 3log3 (2x2 - 1)

+2
Answers (2)
  1. 17 February, 04:37
    0
    Step 1

    log3 (x + 2) = log3 (2x² - 1)

    Step 2

    x + 2 = 2x² - 1

    Step 3

    2x² - x - 3 = 0

    Step 4

    (2x - 3) (x + 1) = 0

    Step 5

    2x - 3 = 0 or x + 1 = 0

    Step 6:

    Potential solutions are - 1 and 3/2

    Step-by-step explanation:

    Step 1

    log3 (x + 2) = log3 (2x² - 1)

    Step 2

    x + 2 = 2x² - 1

    Step 3

    2x² - x - 3 = 0

    Step 4

    2x² - 3x + 2x - 3 = 0

    x (2x - 3) + 1 (2x - 3) = 0

    (2x - 3) (x + 1) = 0

    Step 5

    2x - 3 = 0 or x + 1 = 0

    Step 6:

    x = 3/2 or x = - 1

    Potential solutions are - 1 and 3/2
  2. 17 February, 04:37
    0
    in short 4, 3, 6, 5, 2,1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Order the steps to solve the equation log3 (x + 2) = log3 (2x2 - 1) from 1 to 6. 0 = (2x - 3) (x + 1) 0 = 2x2 - x - 3 Potential solutions ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers