Victoria wants to estimate the mean weight of apples in her orchard. She'll sample n apples and make a 95%
confidence interval for the mean weight. She is willing to use 0 = 15 grams as an estimate of the standard
deviation, and she wants the margin of error to be no more than 5 grams.
Which of these is the smallest approximate sample size required to obtain the desired margin of error?
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Victoria wants to estimate the mean weight of apples in her orchard. She'll sample n apples and make a 95% confidence interval for the mean ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers
You Might be Interested in
Why do ratios use multiplication
Answers (1)
A recent poll of 380 randomly selected Americans showed that 24% ( = 0.24) are happy with their cell phone carriers. The country's largest cell phone carrier would like to know, within a 90% confidence level, the margin of error for this poll.
Answers (1)
Determine how many square inches of wrapping paper you need to wrap a box that is 8 inches wide, 12 inches long, and 2 inches deep with no overlap.
Answers (1)
Solve the system. Tell how many solutions the system has. -2x + 4y = 9 x-27 = - 7
Answers (1)
How many times does 9 go into 777?
Answers (1)
New Questions in Mathematics
Sam added two fractions together and got 7/8 as the answer. Write down two fractions that Sam could of added.
Answers (1)
A sign language club made $627.50 from selling popcorn at a festival. The popcorn cost the club $95.00. Which expression represents the amount of money that was raised for each member of the club?
Answers (1)
In order to avoid a training violation, 85% of your store's employees must complete diversity training by the end of the week. You have 142 employees at your store and 91 have currently completed the training.
Answers (1)
Oprah looks at this histogram of a distribution with a mean of 6.7 grams and a standard deviation of 1 gram. She claims that approximately 68% of the data is between 5.7 and 7.7 grams. What is the error in her thinking?
Answers (1)
16/1337 answer of division
Answers (1)