Radio signals travel at 3*10^ (8) meters per second. How many seconds will it take for a radio signal to travel from a sadelite to the surface of the Earth if the satelite is orbiting at a height of 7.5*10^ (7)

* is multiplication

^ in front of a number means that

0.12s

Step-by-step explanation:

In this problem we are given with the speed of the signal and the distance travelled and is asked to determine the time of travel. IN this case, the expression that can be applied is

time = distance / speed

= (3.6 * 10⁷ m) / (3 * 10⁸ m/s)

= (3.6 / 3) * 10⁷⁻⁸ s

= 1.2 * 10⁻¹ s

t = 0.12 s

Answer:0.4

Step-by-step explanation:

might be wrong but if the satellite is orbiting at a height of 7.5*10^7 (meters?) then it should be 0.4 seconds.

3*10^8=300,000,000

7.5*10^7=75,000,000

300,000,000/75,000,000=0.4