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13 November, 10:29

Determine the order of the given differential equation. t3d3y/dt3 + t dy/dt + 2y = sin t

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  1. 13 November, 10:51
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    Answer: Order 3 (the differential equation is a 3rd order differential equation)

    Step-by-step explanation:

    Given the equation;

    t3d3y/dt3 + t dy/dt + 2y = sin t

    Order of a differential equation is the nth derivative of the highest derivative in the differential equation.

    For the given equation the highest derivative is d^3y/dt^3, which is the 3rd derivative of y.

    Therefore, the order of the differential equation is 3.
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