Ask Question
11 June, 05:56

3. Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.

(a) On what percent of the days last year did the factory produce 20,555 skateboards or fewer?

(b) On what percent of the days last year did the factory produce 20,610 skateboards or more?

(c) On what percent of the days last year did the factory produce 20,445 skateboards or fewer?

+3
Answers (1)
  1. 11 June, 05:58
    0
    Let x be a random variable representing the number of skateboards produced

    a.) P (x ≤ 20,555) = P (z ≤ (20,555 - 20,500) / 55) = P (z ≤ 1) = 0.84134 = 84.1%

    b.) P (x ≥ 20,610) = P (z ≥ (20,610 - 20,500) / 55) = P (z ≥ 2) = 1 - P (z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

    c.) P (x ≤ 20,445) = P (z ≤ (20,445 - 20,500) / 55) = P (z ≤ - 1) = 1 - P (z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “3. Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers