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28 February, 14:39

Show that f (x) = (x-2) ^3+8 is one to one algebraically

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  1. 28 February, 14:58
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    What im thinking is this: F (a) = f (b) so have 2 equations written and plug a into one and b in the other

    (a-2) ^3+8 = a^3-8+8 = a^3

    = a^3 = b^3 square root both side = a=b

    (b-2) ^3+8 = b^3-8+8 = b^3

    Thus it is 1:1.
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