A bag contains 3 blue marbles, 5 green marbles, 4 red marbles, and 6 yellow marbles. Event A = drawing a blue marble on the first draw Event B = drawing a yellow marble on the second draw If Jasmine draws two marbles from the bag, one after the other and doesn't replace them, what is P (B|A) expressed in simplest form?

P (B|A) = 2/9

Step-by-step explanation:

Let A be the event that the first draw is blue marble

Let B be the event that the second draw is yellow marble.

P (B|A) = P (B∩A) / P (A) since P (A) ≠ 0

P (B∩A) = P (B) * P (A|B)

P (B) = 6 / (3+5+4+6)

P (B) = 6/18

P (B) = 1/3

P (A|B) = 6/3

P (A|B) = 2

P (B∩A) = 1/3 * 2

P (B∩A) = 2/3

P (B|A) = P (B∩A) / P (A)

P (B|A) = (2/3) / 3

P (B|A) = 2/3 * 1/3

P (B|A) = 2/9