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4 March, 20:58

After flying between two black holes, our engines have been a bit janky. The probability of one of any of our 8 power couplings failing is 10%: What's the probability none fail? What's the probability one fails? What's the probability four fail? What's the probability six fail? What's the probability eight fail?

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  1. 4 March, 21:04
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    Step-by-step explanation:

    We would apply the formula for binomial distribution. It is expressed as

    P (x = r) = nCr * q^ (n - r) * p^r

    Where

    p represents probability of success

    q represents probability of failure.

    n represents number of sample.

    From the information given,

    p = 10% = 10/100 = 0.1

    q = 1 - q = 1 - 0.1 = 0.9

    n = 8

    1) The probability that none fails is

    P (x = 0) = 8C0 * 0.9^ (8 - 0) * 0.1^0

    P (x = 0) = 0.43

    2) The probability that one fails is

    P (x = 1) = 8C1 * 0.9^ (8 - 1) * 0.1^1

    P (x = 1) = 0.38

    3) The probability that four fails is

    P (x = 4) = 8C4 * 0.9^ (8 - 4) * 0.1^4

    P (x = 4) = 0.0046

    3) The probability that six fails is

    P (x = 6) = 8C6 * 0.9^ (8 - 6) * 0.1^6

    P (x = 6) = 0.00002268

    4) The probability that eight fails is

    P (x = 8) = 8C8 * 0.1^ (8 - 8) * 0.1^8

    P (x = 8) = 0.00000001
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