F (x) = T-2 (X+4) ^2 where t is the constant. If f (-8.3) = f (a) and a > 0 what is the value of a?

Question

Shirley Whitney

Mathematics

27 April, 14:13

F (x) = T-2 (X+4) ^2 where t is the constant. If f (-8.3) = f (a) and a > 0 what is the value of a?

+5

Answers (1)

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Esperanza Kelley · Answer 1

We are given the equation:

F (x) = T - 2 (x + 4) ^2 - - - > equation 1

Since we know that f (-8.3) = f (a) and a>0, therefore from equation 1 we can generate that:

(x + 4) ^2 = (a + 4) ^2

(-8.3 + 4) ^2 = (a + 4) ^2

(-4.3) ^2 = (a + 4) ^2

(a + 4) ^2 = 18.49

a + 4 = 4.3

a = 0.3