A nursery builds protective cylindrical covers, as shown, to protect seedlings from frost. The cover has a top, but no bottom. How many square feet of flexible plastic will be needed to build three dozen of the covers? The flexible plastic is sold by the square foot. the radius is 4 in and the height is 10 in

Question

Anika Weber

Mathematics

2 July, 18:53

A nursery builds protective cylindrical covers, as shown, to protect seedlings from frost. The cover has a top, but no bottom. How many square feet of flexible plastic will be needed to build three dozen of the covers? The flexible plastic is sold by the square foot. the radius is 4 in and the height is 10 in

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Jacoby · Answer 1

414.48 square feet is needed to make 3 dozen of the covers.

Step-by-step explanation:Step 1: Find the circumference, perimeter, of the circle.

To find the circumference, you multiply the 4 by π, and π is 3.14, and you get 12.56.

Step 2: Find the area of the side, not including the circle.

The 12.56 is literally the length of the side. The width is the height of the cover which is 10 inches. 12.56 multiplied by 10 is 125.6 square inches.

Step 3: Add them up.

125.6 + 12.56 is 138.16

Step 4: Multiply 138.16 by three dozen (36 [a dozen is 12]).

138.16 multiplied by 36 is 4973.76 square inches.

Step 5: Convert 4973.76 square inches to square feet.

12 inches is 1 foot so we divide 4973.76 by 12. You get 414.48 square feet.